6a^2-13a+7=0

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Solution for 6a^2-13a+7=0 equation: 



6a^2-13a+7=0

a = 6; b = -13; c = +7;
Δ = b2-4ac
Δ = -132-4·6·7
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$


$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-1}{2*6}=\frac{12}{12}
=1
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+1}{2*6}=\frac{14}{12}
=1+1/6
$

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